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修复FullUrl()未url转义导致的bug
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@@ -47,8 +47,6 @@ typedef void* mk_parser;
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API_EXPORT const char* API_CALL mk_parser_get_method(const mk_parser ctx);
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//Parser::Url(),获取HTTP的访问url(不包括?后面的参数)
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API_EXPORT const char* API_CALL mk_parser_get_url(const mk_parser ctx);
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//Parser::FullUrl(),包括?后面的参数
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API_EXPORT const char* API_CALL mk_parser_get_full_url(const mk_parser ctx);
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//Parser::Params(),?后面的参数字符串
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API_EXPORT const char* API_CALL mk_parser_get_url_params(const mk_parser ctx);
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//Parser::getUrlArgs()["key"],获取?后面的参数中的特定参数
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